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5t^2-100t+375=0
a = 5; b = -100; c = +375;
Δ = b2-4ac
Δ = -1002-4·5·375
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-50}{2*5}=\frac{50}{10} =5 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+50}{2*5}=\frac{150}{10} =15 $
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